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If α, β, γ be the zeroes of the polynomial x3 – 6x2 – x + 3, then the values of (αβ + βγ + γα) = ? (a) -1 (b) 1 (c) -5 (d) 3 |
Answer» (a) -1 Here, p(x) = x3 – 6x2 – x + 3 Comparing the given polynomial with x3 – (α + β + γ) x2 + (αβ + βγ + γα) x – αβγ, we get: (αβ + βγ + γα) = -1 |
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