1.

If α, β, γ be the zeroes of the polynomial x3 – 6x2 – x + 3, then the values of (αβ + βγ + γα) = ? (a) -1 (b) 1 (c) -5 (d) 3

Answer»

(a) -1 

Here, 

p(x) = x3 – 6x2 – x + 3 

Comparing the given polynomial with x3 – (α + β + γ) x2 + (αβ + βγ + γα) x – αβγ, 

we get:

(αβ + βγ + γα) = -1



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