InterviewSolution
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InterviewSolution
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If α, β, γ be the zeroes of the polynomial x3 – 6x2 – x + 30, then (αβ + βγ + γα) = ? (a) -1 (b) 1 (c) -5 (d) 30 |
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Answer» (a) -1 It is given that α, β and γ are the zeroes of x3 – 6x2 – x + 30. ∴ (αβ + βγ + γα) = \(\frac{coefficient\,of\,x}{coefficient\,of\,x^3}\) = \(\frac{-1}1\) = - 1 |
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