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If `A+B=pi/3 and cos A+cos B=1,` then which of the following is/are true ?A. `cos(A-B)=1/3`B. `|cosA-cosB|=sqrt(2/3)`C. `cos(A-B)=-2/3`D. `|cosA-cosB|=(1)/(2sqrt3)` |
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Answer» Correct Answer - B::C We have, `cosA+cos B=1` `implies2 cos ""(A+B)/(2)cos""(A-B)/(2)=1` `impliescos""(A-B)/(2)=(1)/(sqrt(3))" "[becauseA+B=(pi)/(3)]` `implies2 cos^(2)""((A-B)/(2))-1=2/3-1impliescos(A-B)=-1/3` Now, `|cosA-cosB|` `=|2sin((A+B)/(2))sin((B-A)/(2))|` `=|2sin""(pi)/(6)sin((A-B)/(2))|` `= |sin((A-B)/(2))|=sqrt(1-cos^(2)((A-B)/(2)))=sqrt(1-(1)/(3))=sqrt((2)/(3))` So, option (b) is also true, |
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