1.

If $(a+b):\sqrt{ab}= 4:1 $, where a > b > 0, then a:b is1). $(2 + \sqrt{3}) : (2 - \sqrt{3})$2). $(2 - \sqrt{3}) : (2 + \sqrt{3})$3). $(3 + \sqrt{2}) : (3 - \sqrt{2})$4). $(3 - \sqrt{2}) : (3 + \sqrt{2})$

Answer»

it from previous year SSC papers, OPTION 1 is the RIGHT answer



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