If a ball fallen freely from 'h' height reaches in time 't' at ground, then what will be the time when it reaches at height h/2 ?

If a ball fallen freely from 'h' height reaches in time 't' at ground,

1.	If a ball fallen freely from 'h' height reaches in time 't' at ground, then what will be the time when it reaches at height h/2 ?
Answer» Solution :For freefall,` t = sqrt ((2h)/(g)) ""…(1)` Time taken to reach at `(H)/(2),` `t . = sqrt ((2h)/(2G)) [ because h . =(h)/(2)]` ` therefore t. = sqrt ((h)/(g)) ""...(2)` By taking ratio of EQUATION (2) and (1). `(t.)/(t) = sqrt((h)/(g)XX (g)/(2h)) = (1)/(sqrt2)` `therefore t .= (t)/(sqrt2) s`