If →a,→band→care unit vectors such that→a.→b=→a.→c=0 and the angle between→band→cisπ6,then prove that (i)→a=±2(→b×→c)(ii)[→a+→b →b+→c →c+→a]=±1.

If →a,→band→care unit vectors such that→a.→b=→a.→c=0 and

1.	If →a,→band→care unit vectors such that→a.→b=→a.→c=0 and the angle between→band→cisπ6,then prove that (i)→a=±2(→b×→c)(ii)[→a+→b →b+→c →c+→a]=±1.
Answer» If $\to a, \to b and \to c are unit vectors such that \to a . \to b = \to a . \to c = 0 and the angle between \to b and \to c is \frac{π}{6}, then prove that$ $(i) \to a = \pm 2 (\to b \times \to c) (i i) [\to a + \to b \to b + \to c \to c + \to a] = \pm 1.$

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If →a,→band→care unit vectors such that→a.→b=→a.→c=0 and the angle between→band→cisπ6,then prove that (i)→a=±2(→b×→c)(ii)[→a+→b →b+→c →c+→a]=±1.

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