1.

If \(A=\begin{bmatrix}2 & 0 & 1 \\2 & 1 & 3 \\1 & -1 & 0\end{bmatrix},\) find A2 − 5A + 4I and hence find a matrix X such that A2 − 5A + 4I + X = 0.A = [2, 0, 1][2, 1, 3][1, -1, 0], find A2 − 5A + 4I

Answer»

\(\begin{bmatrix} -1 & -1 & 3 \\ -1 & -3 & -10 \\ -5 & 4 & -6 \end{bmatrix},X = \begin{bmatrix} 1 & 1 & 3 \\ 1 & 3 & 10 \\ 5 & -4 & 6 \end{bmatrix}\)

[-1, -1, 3][-1, -3, -10][-5, 4, -6], X = [1, 1, 3][1, 3, 10][5, -4, 6]



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