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If A = \(\begin{pmatrix} 1 & k & 3 \\ 3 & k &-2 \\ 2 & 3 & -4 \end{pmatrix}\)is singular then k = ?((1,k,3),(3,k,-2),(2,3,-4))A. 16/3B. 34/3C. 33/2D. none of these |
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Answer» When a given matrix is singular then the given matrix determinant is 0. |A| = 0 Given, A = \(\begin{pmatrix} 1 & k & 3 \\ 3 & k &-2 \\ 2 & 3 & -4 \end{pmatrix}\) |A| = 0 1(-4k + 6) –k(-12 + 4) +3 (9 -2k)= 0 -4k + 6 +12k -4k + 27 -6k = 0 -2k +33 = 0 k = 33/2, |
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