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If A = \(\begin{pmatrix}3&λ&2 \\1 &2&5\\2&1&1\end{pmatrix}\) is not invertible then λ = ?A. 2 B. 1 C. -1 D. 0 |
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Answer» = \(\begin{pmatrix} 3&λ&2 \\ 1 &2&5\\2&1&1 \end{pmatrix}\) │A│= 0 1(2 x 1 – 5 x 1) - (1 x 1 – 5 x 2) + 2 ( 1 x 1 – 2 x 2) = 0 -3 + 9 λ - 6 = 0 9 λ = 9 λ = 1 |
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