InterviewSolution
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InterviewSolution
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If a block of mass m lying on a frictionless inclined plane of length L, height h and angle of inclination θ, then the time take taken to reach the bottom is –(a) g sing θ(b) sin θ \(\sqrt {\frac{2h}{g}}\)(c) sin θ \(\sqrt {\frac{g}{h}}\)(d) \(\frac{1}{sinθ}\) \(\sqrt {\frac{2h}{g}}\) |
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Answer» (d) \(\frac{1}{sinθ}\) \(\sqrt {\frac{2h}{g}}\) |
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