If a body moves on the circumference of a circle with a speed equal to that which it would acquire by falling freely through half the radius of the circle, prove that its centripetal acceleration is equal to the acceleration of the free fall.

If a body moves on the circumference of a circle with a speed equal to

1.	If a body moves on the circumference of a circle with a speed equal to that which it would acquire by falling freely through half the radius of the circle, prove that its centripetal acceleration is equal to the acceleration of the free fall.
Answer» Solution :`v^(2) =0 + 2g xx (r//2) = GR, a = v^(2)//r = rg//r = G`