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If a body of mass 0.98 kg is made to oscillate on a spring of force constant 4.84N/m,the angular frequency of the body isA) 1.22rad/s B) 2.22rad/s C) 3.22rad/s D) 4.22rad/s |
Answer» \(\omega\) = \(\sqrt{\frac{k}{m}}\) = \(\sqrt{\frac{4.84}{0.98}}\) = 2.22 rad / sec |
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