1.

If a bullet of mass 5 g moving with avelocityof 100m//s penetrates a wooden block upto 6cm . Find the average force imposed.

Answer»

Solution :`u=100 m//s , v=0, S = 6XX10^(-2)m, a=? , v^(2)-u^(2)=2as`
`0^(2)-(100)^(2)=2xxaxx6xx10^(-2)`
`a=(-100xx100)/(2xx6xx10^(-2)),a=-1/(12)xx10^(6) m//s`
`F=ma =5xx10^(-3)xx[-1/(12)xx10^(6)],F= (-5000)/(12)=-417 n`
Retarding forceF=417 N


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