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If a bullet of mass 5 g moving with avelocityof 100m//s penetrates a wooden block upto 6cm . Find the average force imposed. |
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Answer» Solution :`u=100 m//s , v=0, S = 6XX10^(-2)m, a=? , v^(2)-u^(2)=2as` `0^(2)-(100)^(2)=2xxaxx6xx10^(-2)` `a=(-100xx100)/(2xx6xx10^(-2)),a=-1/(12)xx10^(6) m//s` `F=ma =5xx10^(-3)xx[-1/(12)xx10^(6)],F= (-5000)/(12)=-417 n` Retarding forceF=417 N |
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