If a > c; show that abc – cba = 99(a – c).

1.	If a > c; show that abc – cba = 99(a – c).
Answer» Given, a > c To show : abc – cba = 99(a – c) Proof: abc = 100a + 10b + c ……….(i) (By using property 3) cba = 100c + 10b + a ………..(ii) (By using property 3) Subtracting, equation (ii) from (i), we get abc – cba = 100a + c – 100c – a abc – cba = 99a – 99c abc – cba = 99(a – c) Hence proved.

Answer»

Given, a > c

To show : abc – cba = 99(a – c)

Proof: abc = 100a + 10b + c ……….(i) (By using property 3)

cba = 100c + 10b + a ………..(ii)

(By using property 3)

Subtracting, equation (ii) from (i), we get

abc – cba = 100a + c – 100c – a abc –

cba = 99a – 99c abc – cba = 99(a – c) Hence proved.

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