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If a complex number having absolute value of √2 is making 45° angle with x-axis in third quadrant, then it can be written as –1. [r, θ] = \(\left[ {\sqrt 2 ,\frac{{3\pi }}{4}} \right]\)2. [r, θ] = \(\left[ {\sqrt 2 ,\frac{{\pi }}{4}} \right]\)3. [r, θ] = \(\left[ {\sqrt 2 ,-\frac{{3\pi }}{4}} \right]\)4. [r, θ] = \(\left[ {\sqrt 2 ,-\frac{{\pi }}{4}} \right]\) |
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Answer» Correct Answer - Option 3 : [r, θ] = \(\left[ {\sqrt 2 ,-\frac{{3\pi }}{4}} \right]\) CONCEPT: Point P is uniquely determined by the ordered pair of real numbers (r, θ), called the polar coordinates of the point P. If P represent the nonzero complex number z = x + iy. Here \(r = \sqrt {{x^2} + {y^2}} = \left| z \right|\) is called modulus of the given complex number. The argument of Z is measured from the positive x-axis only. Let z = r (cos θ + i sin θ) is a polar form of any complex number then following ways are used while writing θ for different quadrants – For the first quadrant, \({\rm{\theta }} = {\tan ^{ - 1}}\frac{{\rm{y}}}{{\rm{x}}}\) For the second quadrant \({\rm{\theta }} = {\rm{\pi }} - {\tan ^{ - 1}}\frac{{\rm{y}}}{{\rm{x}}}\) For the third quadrant \({\rm{\theta }} = - {\rm{\pi }} + {\tan ^{ - 1}}\frac{{\rm{y}}}{{\rm{x}}}\) For the fourth quadrant \({\rm{\theta }} = - {\rm{\;ta}}{{\rm{n}}^{ - 1}}\frac{{\rm{y}}}{{\rm{x}}}\) CALCULATION: Given that \(\left| z \right| = \sqrt 2 \) and angle with x-axis is 45°. Since its in the third quadrant - ∴ \(\theta = - \pi + \frac{\pi }{4} = - \frac{{3\pi }}{4}\) ⇒ [r, θ] = \(\left[ {\sqrt 2 , - \frac{{3\pi }}{4}} \right]\) |
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