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If a conductor is moving in the north direction and magnetic field is applied vertically upwards, the change in flux is `2xx10^(-4)` Wb within 2s. Is the resistance of conductor is `5Omega`, then the magnitude of induced current will beA. 0.02 mAB. 0.2 mAC. 0.002 mAD. 2 mA |
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Answer» Correct Answer - A `e=(dphi)/(dt)=(2xx10^(-4))/(2)=1xx10^(-4)V` `I=(e)/(R)=(1xx10^(-4))/(5)=0.02mA` |
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