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| 1. |
If a constant torque of 500 Nm turns a wheel of moment of inertia 100 kg-m^2 about an axis through its centre, find the angular velocity and the kinetic energy gained in 2 seconds, |
| Answer» SOLUTION :`prop = tau//l = 500//100 = 5 "rads"^(-2), OMEGA = at = 10 "rads"^(-1), K.E =(1//2)Iomega^(2) = 500 J` | |