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If a copper wire of length 0.9 m and cross section `1mm^(2)` is stretched by a load of 1 kg then the extension in the wire will be `(Y_(c )=1.2xx10^(11)N//m^(2) and g=10m//s^(2))`A. 0.013 mmB. 0.075 mmC. 0.11 mmD. 0.13 mm |
Answer» Correct Answer - B `e=(FL)/(Ay)=(1xx10xx0.9)/(10^(-6)xx1.2xx10^(11))` `=(3)/(4) xx 10^(-4) = 0.75 xx 10^(-4)m` `=0.075 mm`. |
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