Saved Bookmarks
| 1. |
If a curve y=asqrtx+bx passes through the point (1,2) and the area bounded by the curve, line x=4 and x-axis is 8 square units, then |
|
Answer» `a=3,b=-1` `therefore2=a+b""...(i)` It is given that `UNDERSET(0)overset(4)(INT)(asqrtx+bx)dx=8` `IMPLIES[(2)/(3)ax^(3//2)+b/2x^(2)]_(0)^(4)=8` `implies16/3a+8b=8implies2/3a+b=1""...(ii)` Solving (i)and (ii), we get `a=3, b=-1.` |
|