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If a curve `y=asqrtx+bx` passes through the point (1,2) and the area bounded by the curve, line x=4 and x-axis is 8 square units, thenA. `a=3,b=-1`B. `a=3,b=1`C. `a=-3,b=1`D. `a=-3,b=-1` |
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Answer» Correct Answer - a It is given that `y=asqrtx+bx` passes through the point (1,2). `therefore2=a+b" "...(i)` It is given that `underset(0)overset(4)(int)(asqrtx+bx)dx=8` `implies[(2)/(3)ax^(3//2)+b/2x^(2)]_(0)^(4)=8` `implies16/3a+8b=8implies2/3a+b=1" "...(ii)` Solving (i)and (ii), we get `a=3, b=-1.` |
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