1.

If A + D > C + E, C + D = 2B nd B + E > C + D, it necessarily follows that(A) A + B > 2D (B) B + D > C + E (C) A + D > B + E (D) A + D > B + C

Answer»

(D) A + B > C + E

=> A + D > (2B - D) + E (∴ C + D = 2B)

=> A + D > (B + E) + (B - D)

=> A + D > (C + D) + (B - D)

=> A + D > B + C.



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