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If A + D > C + E, C + D = 2B nd B + E > C + D, it necessarily follows that(A) A + B > 2D (B) B + D > C + E (C) A + D > B + E (D) A + D > B + C |
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Answer» (D) A + B > C + E => A + D > (2B - D) + E (∴ C + D = 2B) => A + D > (B + E) + (B - D) => A + D > (C + D) + (B - D) => A + D > B + C. |
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