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If a force F=(3^i+4^j+5^k) N is acting on a particle moving on a circle of radius 2 m with a speed increasing at the rate of 2 m/s2. All points on the circle satisfy the equation 3x+4y+5z=0. The power due to the force on the particle is |
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Answer» If a force F=(3^i+4^j+5^k) N is acting on a particle moving on a circle of radius 2 m with a speed increasing at the rate of 2 m/s2. All points on the circle satisfy the equation 3x+4y+5z=0. The power due to the force on the particle is |
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