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If A = \(\frac{2x+1}{2x-1}\) and B = \(\frac{2x-1}{2x+1},\) then A - B is equal to :(a) \(\frac{1}{4x^2-1}\)(b) \(\frac{8}{4x^2-1}\)(c) \(\frac{-2}{4x^2-1}\)(d) \(\frac{4x}{4x^2-1}\) |
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Answer» (b) \(\frac{8}{4x^2-1}\) A - B = \(\frac{2x+1}{2x-1}\) - \(\frac{2x-1}{2x+1}\) = \(\frac{(2x+1)^2 -(2x-1)^2}{(2x-1)(2x+1)}\) = \(\frac{(4x^2+4x+1)-(4x^2-4x+1)}{4x^2-1}\) = \(\frac{8}{4x^2-1}\) |
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