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If \(a^\frac13+b^\frac13+c^\frac13=0,\) then the value of (a + b + c)3 will be :(a) 9 a2b2c2(b) 3abc (c) 6abc (d) 27abc |
Answer» (d) 27 abc \(a^\frac13+b^\frac13+c^\frac13=0,\) \((a^\frac13)^3+(b^\frac13)^3+(c^\frac13)^3\) = \(3\,a^\frac13+b^\frac13+c^\frac13\) ⇒ a + b + c = \(3(abc)^\frac13\) ⇒ (a + b + c)3 = 27 abc. |
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