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If a function f(x) satisfies f(x)+f(y)f(x+y)=1,where x,y∈R and f(2) is the mean of roots of x2−6x+8=0, then the value of 3sin(f(3)π)+4cos(f(1)π) is |
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Answer» If a function f(x) satisfies f(x)+f(y)f(x+y)=1, where x,y∈R and f(2) is the mean of roots of x2−6x+8=0, then the value of 3sin(f(3)π)+4cos(f(1)π) is |
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