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If a function is invertible the graph of its inverse is the mirror image of the function in y=x. If f^(-1)(x) is the inverse function of f(x), then f(f^(-1)(x))=f^(-1)(f(x))=x. If f(x)=ln[((100+x)e^(x^(3)))/((100-x))], then the graph of f^(-1)(x) will be symmetrical about x+y=1 |
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Answer» `x+y=1` |
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