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If a gas occupies 30 L at `27^(@)C` and 1 atm, what volume would it occupy at `227^(@)C` and 5 atm?

Answer» `{:("Initial condition",,"Final condition"),(V_(1) = 301,,V_(2) =?),(P_(1)=1" atm",,P_(2) = 5" atm"),(T_(1) = 27^(@)C = 300 K,,T_(2) = 227^(@)C = 500K):}`
According to gas equation, `(P_(1)V_(1))/T_(1)= (P_(2)V_(2))/T_(2) V_(2)=(P_(1)V_1)/T_(1) xxT_(2)/P_(2) = (30 xx1)/300xx500/5 = 10 ` L


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