1.

If A is non-singular and (A – 2I) (A – 4I) = 0, then 1/6 A + 4/3A-1 = (a)   I (b)  0 (c)  2I (d)  6I

Answer»

Correct option  (a)  I

Explanation:

(A – 2I) (A – 4I) = 0

A– 2A – 4A + 8I = 0

A– 6A + 8I = 0 

A –1(A2 – 6A + 8I) =

A – 10 (Pre multiply by A–1

A–1A2 – 6A – 1 +  8A  – 1I = 0

A – 6I + 8A – 1 = 0

A + 8A – 1 = 6I

1/6A + 4/3A-1  = 1



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