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If ‘a’ is the aperture of telescope and ‘λ’ is the wavelength of light then resolving power of telescope is ______.(A) \(\frac{λ}{1.22a}\)(B) \(\frac{1.22a}{λ}\)(C) \(\frac{1.22λ}{a}\)(D) \(\frac{a}{1.22λ}\) |
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Answer» Answer is: (D) \(\frac{a}{1.22λ}\) |
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