1.

If A is the area of each plate, charge on it is q and potential difference is V then the distance between the parallel plate capacitor isA. `(epsi_(0)AV)/(2q)`B. `(epsi_(0)AV)/(q)`C. `(2epsi_(0)AV)/(q)`D. `(AV)/(q)`

Answer» Correct Answer - B
`V=E*d`
`d=V/E=V/(sigma/epsi_(0))`
`=(V/q)/(Aepsi_(0))=(VAepsi_(0))/q`


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