

InterviewSolution
Saved Bookmarks
1. |
If A is the area of each plate, charge on it is q and potential difference is V then the distance between the parallel plate capacitor isA. `(epsi_(0)AV)/(2q)`B. `(epsi_(0)AV)/(q)`C. `(2epsi_(0)AV)/(q)`D. `(AV)/(q)` |
Answer» Correct Answer - B `V=E*d` `d=V/E=V/(sigma/epsi_(0))` `=(V/q)/(Aepsi_(0))=(VAepsi_(0))/q` |
|