if a is the length of the side of a cube, the distance between the body-centred atom and one corner atom in the cube will be

if a is the length of the side of a cube, the distance between the bod

1.	if a is the length of the side of a cube, the distance between the body-centred atom and one corner atom in the cube will be
Answer» `2sqrt3a` `4/sqrt3a` `sqrt3/4a` `sqrt3/2 a` Solution :In BODY-centred cubic (BCC), oppositely charged ions touch each other along the body diagonal `therefore` Body diagonal, AE=`2r_(Cs^+)+ 2r_(Cl^-)` But body diagonal =`sqrt3a` (From right angled `triangleCDE`, CE=`SQRT(a^2+a^2)=sqrt2a` From right angled `triangle ACE` , `AE=sqrt(AC^2+CE^2)=sqrt(a^2+2a^2)=sqrt(3a^2)=sqrt3a`) `therefore 2(r_(Cs^+)+r_(Cl^-))=sqrt3a` or `r_(Cs^+) +r_(Cl^(-))=sqrt3/2a`