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If a=lambdahati+2hatj-3hatk, b=2hati+lambdahatj-hatk, c=hati+2hatj+hatk and [abc]=6, then lambda is equal to |
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Answer» `-8 or 3` On applying `C_(1) to C_(1)-C_(3)`, we get `=|(lambda+3, 2 , -3),(3, lambda, -1),(0,2,1)|` `(lambda+3)(lambda+2)-3(2+6)=0` `RARR lambda^(2)+5lambda - 24=0` `rArr lambda =- 8 or 3 ` |
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