1.

If a long hollow copper pipe carries a current, then magnetic field is produced:

Answer»

inside the pipe only
outside the pipe only
both inside and outside the pipe
no where

Solution :According to Ampere's circuital law,
`B(2pir)=mu_(0)xx0`
or `B=0`
So, inside a hollow metallic (copper) pipe carrying CURRENT, the magnetic field is zero.
But for external points, the whole current BEHAVES as if were concentrated at the axis only, so outside
`B_(0)=(mu_(0)i)/(2pir)`
Then, the magnetic field is produced outside the pipe only


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