InterviewSolution
`sum_(K=1)^(OO)((-1)^(k)B^(k))/(k)` `sum_(k=1)^(oo)((-1)^(k-1)b^(k))/(k!)` `sum_(k=1)^(oo)((-1)^(k)b^(k))/((k-1)!)` `sum_(k=1)^(oo)((-1)^(k-1)b^(k))/((k+1)!)`
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