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If a man submits to a diet of 9500 kJ per day and expands energy in all forms to a total of 12000 kJ per day. What is the change in internal energy per day? If the energy lost was stored as sucrose (1632 kJ per 100 g), how many days should it take to lose 1 kg? (Ignore water loss for this problem). |
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Answer» ∆E = 12000 − 9500 = 2500 kJ 100 g of sucrose has energy = 1632 kJ \(\therefore\) 1000 g of sucrose has energy = 1632 × 10 = 16320 kJ Now 2500 kJ of energy of lost in one day \(\therefore\) 16320 kJ of energy is lost in = \(\frac{1}{2500}\)x 16320 = 6.5 days. |
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