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If a metal with atomic mass 209 crystallizes in a simple cubic lattice what is the edge length of its unit cell. (Given d = 91.5 kg m-3). |
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Answer» As we know, density 'd' = \(\frac{ƵM}{a^3N_A}\) a3 = \(\frac{1\times209 g/mol}{6.022\times10^{23}\times91.5 \times 10^3 g/m^3}\) a3 = 0.3793 x 10-26 m3 a3 = 3.793 x 10-27 m3 a = 1.5595 x 10-9 m a = 1.56 x 10-9 m |
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