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If a monoatomic gas at 17^@C is suddenly compressed to 1/8th of initial volume B, then the new temperature will be ……. |
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Answer» 887 K `T_1V_1^(gamma-1)=T_V_2^(gamma-1)` `THEREFORE T_2=T_1(V_1/V_2)^(gamma-1)` but `T_1`=17+273 =290 K `=290xx(8)^(5/3-1) "" [because gamma=5/3]` `=290xx(2^3)^(2/3)` =290 x 4 `therefore T_2` = 1160 K |
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