1.

If a monoatomic gas at 17^@C is suddenly compressed to 1/8th of initial volume B, then the new temperature will be …….

Answer»

887 K
36.25 K
2320 K
1160 K

Solution :If a gas compressed suddenly then ADIABATIC process occur and in this process.
`T_1V_1^(gamma-1)=T_V_2^(gamma-1)`
`THEREFORE T_2=T_1(V_1/V_2)^(gamma-1)` but `T_1`=17+273 =290 K
`=290xx(8)^(5/3-1) "" [because gamma=5/3]`
`=290xx(2^3)^(2/3)`
=290 x 4
`therefore T_2` = 1160 K


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