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If A=∑nr=0(nCrcos(n−r)x.sinrx),B=2n sin nx and C=1!0!n−1+1!3!n−3+1!5!n−5+⋯+1!n−1!1, then |
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Answer» If A=∑nr=0(nCrcos(n−r)x.sinrx),B=2n sin nx and C=1!0!n−1+1!3!n−3+1!5!n−5+⋯+1!n−1!1, then |
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