If a number is 2^2 x 3^1 x 5^0 and b is 2^2 x 3^1 x 5^1 then hcfof a, b is?(a) 2^2 x 3^1 x 5^1(b) 2^2 x 3^2 x 5^2(c) 2^1 x 3^1 x 5^0(d) 2^2 x 3^2 x 5^0I got this question in exam.I'd like to ask this question from Number Theory topic in division Number Theory and Cryptography of Discrete Mathematics

If a number is 2^2 x 3^1 x 5^0 and b is 2^2 x 3^1 x 5^1 then hcfof a,

1.	If a number is 2^2 x 3^1 x 5^0 and b is 2^2 x 3^1 x 5^1 then hcfof a, b is?(a) 2^2 x 3^1 x 5^1(b) 2^2 x 3^2 x 5^2(c) 2^1 x 3^1 x 5^0(d) 2^2 x 3^2 x 5^0I got this question in exam.I'd like to ask this question from Number Theory topic in division Number Theory and Cryptography of Discrete Mathematics
Answer» Correct choice is (c) 2^1 x 3^1 x 5^0 To EXPLAIN I would say: HCF is the product of sets having LEAST EXPONENT value among a and b.

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