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If `a(p+q)^2+2b p q+c=0a b da(p+r)^2+2b p r+c=0(a!=0)`, then`q r=p^2`b. `q r=p^2+c/a`c. `q r=p^2`d. none of theseA. `qr = p^(2) + (c)/(a)`B. `qr = p^(2)`C. `(q + r)/(a + b) = -(2p)/(a)`D. `(q + r)/(a + b) = -(p)/(a)` |
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Answer» Correct Answer - A::C `q` and `r` are the roots of the equation `a(p + x)^(2) + 2bpx + c = 0` `ax^(2) + 2(a + b)px + ap^(2) + c = 0` `rArr` Product of roots is `qr = (ap^(2) + c)/(a) rArr qr = p^(2) + (c)/(a)` Sum of roots is `q + r = -(2p(a + b))/(a)` |
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