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If a pair of dice is thrown 5 times then find the probability of getting three doublets. |
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Answer» Solution :In a single through of a pair of dice p(a DOUBLET) `=6/36=1/6` p (a non doublet) = 1-p9a doublet)`=1-1/6=5/6` CLEARLY the given experiment is a binomial experiment with n=5 `p=1/6` and `q=5/6` p(3 DOUBLETS in 5 THROW) = `^5C_3p^3q^2=10 cdot(1/6)^3(5/6)^2=250/6^5=125/3888` |
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