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If a parallel plate capacitor has a capacity C, on inserting a dielectric slab of relative permeability K and thickness equal to one-fourth of the plate separation is placed between the plates, then its capacity becomes C'. The value of C'/C will be;{A} K/2(K+1){B} 2K/(K+1){c}5k/(4k+1){d} 4k/(3k+1) |
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Answer» Answer: (d) 4k/(3k+1) |
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