If a particle is moving on an parallel path given by r=b cos omegat hati+asinomegat hatj, then find its radial acceleration along r

If a particle is moving on an parallel path given by r=b cos omegat ha

1.	If a particle is moving on an parallel path given by r=b cos omegat hati+asinomegat hatj, then find its radial acceleration along r
Answer» `omega r` `omega^(2)r` `-omega^(2)r` none of these Solution :(a) `(DR)/(dt)=-bomegat sin hati+aomega cos OMEGAT hatj` `(d^(2)r)/(dt^(2))=-BOMEGA^(2) sin omegat hati+aomega^(2) cos omegat hatj` `(d^(2)r)/(dt^(2))=-omega^(2) [b cos omegat hati+a sin omegat hatj]=-omega^(2)r`