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If a particle of charge `10^(-12)` coulomb moving along the`hat(x)`-direction with a velocity `10^(5)m//s` experiences a force of `10^(-10)` newton in `hat(y)`-direction due to magnetic field. Then the minimum magnetic field isA. `6.25xx10^(3)` tesla in `hat(z)`-directionB. `10^(-15)` tesla in `hat(z)`-directionC. `6.25xx10^(-3)` tesla in `hat(z)` directionD. `10^(-3)` tesla in `hat(z)`-direction |
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Answer» Correct Answer - D `F=qvB sin thetaimpliesB=(f)/(qvsin theta)` `B_(min)=(F)/(qv)` (when `theta=90^(@)`) `:. B_(min)=(F)/(qv)=(10^(-10))/(10^(-12)xx10^(5))=10^(-3)tesla` in `hat(z)`-direction. |
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