Saved Bookmarks
| 1. |
If a particle with `a = kv^(2)` and initial velocity is u then velocity after S displacement. Here `k` is a constantA. `ue^(ks)`B. `2ue^(ks)`C. `ue^(2ks)`D. `2ue^(2ks)` |
|
Answer» Correct Answer - A If a particle ………….. `a = (dV)/(dt)` `v(dv)/(ds) = kv^(2)` `int(dv)/(v)=k int ds` `ln v = ks+c` at `s = 0`, `v = u` `implies lnv = ks + lnu` `implies ln (V)/(u)= ks implies v = ue^(ks)` |
|