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If a plane passes through the point (1, 1, 1) and is perpendicular to the line (x - 1)/3 = (y - 1)/0 = (z - 1)/4, then its perpendicular distance from the origin is - |
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Answer» `3/4` `3(x - 1) + 0(y - 1) + 4(Z -1) = 0` `3X + 4z - 7 = 0` Perpendicular distance from the origin is- `=|(-7)/5| = 7/5`. |
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