1.

If a planet were suddenly stopped in its circular orbit, how much time it would take to fall onto the Sun. Assume the planets time-period of revolution as T.

Answer»

Solution :
For the circular orbit, `T^(2)PROPR^(3)`. When the planet is falling onto the SUN, we can think of its path as a completely flattened ellipse, WHOSE semi-major axis `=(r)/(2)`.
`rArr(T')^(2)prop((r)/(2))^(3)`
Now,`((T')/(T))^(2)=((r//s)/(r))^(3)`,
`(T')^(2)=(T^2)/(8)`,
`T'=(T)/(2sqrt2)`
The required TIME is `(T')/(2)`
`rArrt=(T')/(2)=(T)/(4sqrt2)`
(or) `t=(Tsqrt2)/(8)`


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