If a point P whose position vector is `vec a` lying on the plane ABC where `A(2,3,0), B (3,-2,0), C(2,-1,0)`. Then distance of P from plane ABC is given by-

If a point P whose position vector is `vec a` lying on the plane ABC w

1.	If a point P whose position vector is `vec a` lying on the plane ABC where `A(2,3,0), B (3,-2,0), C(2,-1,0)`. Then distance of P from plane ABC is given by-
Answer» `vecn=vec(AB)vec(AC)` `=(hati-5hatj)(0hati-4hatj)` `=-4hatk` `vec(AP)vecn=\|vec(AP)\|\|vecn\|costheta` `(vecAvecPvecn)/\|(vecn)\|=\|vec(AP)\|costheta` `(veca-(2hati+3hatj)*hatk=d` `vec(AP)=veca-vecb` `d=\|(veca-4hatk)/4\|=\|vecahatk\|` Option 1 is correct.

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If a point P whose position vector is `vec a` lying on the plane ABC where `A(2,3,0), B (3,-2,0), C(2,-1,0)`. Then distance of P from plane ABC is given by-

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