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If a raindrop falls under the influence of the downward gravitational force and the opposing resistive force. Consider a drop of mass 1.00 g falling from a height 1.00 km. It hits the ground with a speed of 50.0 ms^(-1). (1) What is the work done by the gravitational force ? (2) What is the work done by the unknown resistive force ? |
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Answer» Solution :(1) The change in kinetic energy of the drop is `Delta K=(1)/(2)m UPSILON^(2)-0=(1)/(2)xx10^(-3)xx50xx50=1.25 J` WORK done by the gravitational force is `W_(g)=mgh=10^(-3)xx10xx10^(3)=10.0J` (2) The work done by the resistive force on the raindrop. Thus `W_(r )=Delta K - W_(g)=1.25-10=-8.75 J` |
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