If a raindrop falls under the influence of the downward gravitational force and the opposing resistive force. Consider a drop of mass 1.00g falling from a height 1.00km. It hits the ground with a speed of 50.0 ms^(1). (1) What is the work done by the gravitational force ? (2) What is the work done by the unknown resistive force?

If a raindrop falls under the influence of the downward gravitational

1.	If a raindrop falls under the influence of the downward gravitational force and the opposing resistive force. Consider a drop of mass 1.00g falling from a height 1.00km. It hits the ground with a speed of 50.0 ms^(1). (1) What is the work done by the gravitational force ? (2) What is the work done by the unknown resistive force?
Answer» Solution :(1) The chang in kinetic energy of the drop is `DELTA K = (1)/(2) mv^(2) - 0 = (1)/(2) xx 10^(-3) xx 50 xx 50= 1.25J` Work done by the gravitational force is `W_(g)= mg h = 10^(-3) xx 10 xx 10^(3)= 10.0J` (2) The work done by the RESISTIVE force on the RAINDROP. Thus `W_(r )= Delta K- W_(g)` `= 1.25 - 10= -8.75J`